(1/5)^m+4=5

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Solution for (1/5)^m+4=5 equation:



(1/5)^m+4=5
We move all terms to the left:
(1/5)^m+4-(5)=0
Domain of the equation: 5)^m!=0
m!=0/1
m!=0
m∈R
We add all the numbers together, and all the variables
(+1/5)^m+4-5=0
We add all the numbers together, and all the variables
(+1/5)^m-1=0
We multiply all the terms by the denominator
(+1-1*5)^m=0
We add all the numbers together, and all the variables
(-4)^m=0

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